# Python Set issuperset() Method Example

Python Set issuperset() is an inbuilt function that returns True if a **set** has every element of another **set** (passed as an argument). If not, it returns False. The **set** A is said to be the superset of **set** B if all elements of B are in A.

In Python, there are two different approaches of checking whether the given pair of sets are in the superset relationship or not; they are as follows:

- issuperset Method
- >= Operator

**Python Set issuperset() Method**

Before learning the Python issuperset() method, we should be clear with the superset.

If all the values of one set are present in another set, then the second set is called Superset of the first set.

Let’s understand the difference between subset and superset with an example:

Consider this image, there are two sets, **A={1,2,4} and B={1,2,3,4,5}. **So we can see that all the elements of set A are present in set B. So here, B is called *Superset* of set A. Also, set A is called *Subset* of set B.

Python set issuperset() method helps us to find if a set is a superset of another set or not.

The issuperset() method takes iterable (list, tuple, dictionary, set and string) as an argument, if the iterable other than set is passed, it first converts an iterable object to the set object and then checks whether all items of a set ( passed as an argument ) are also present in the set ( on which issuperset method is invoked ).

If yes, then it returns True; otherwise, False.

**Syntax**

First_Set.issuperset(Second_Set)

Here, this syntax will check if **First_Set** is a superset of **Second_Set** or not.

**Return Value**

The issuperset() function returns two types of values:

**True: **If First_Set is a superset of Second_Set

**False: **If First_Set is **not** a superset of Second_Set

See the following code.

# app.py # Declaring two sets # Even nums between 2 and 10 set1 = {2, 4, 6, 8, 10} # Multiple of 4 from 4 to 10 set2 = {4, 8} # Multiple of 4 from 4 to 20 set3 = {4, 8, 12, 16, 20} # priting both the sets print("Set1 is: ", set1) print("Set2 is : ", set2) print("Set3 is: ", set3) # Now we will find if they are disjoint print("Is Set1 Superset of Set2? ", set1.issuperset(set2)) print("Is Set1 Superset of Set3? ", set1.issuperset(set3))

**Output**

Set1 is: {2, 4, 6, 8, 10} Set2 is : {8, 4} Set3 is: {4, 8, 12, 16, 20} Is Set1 Superset of Set2? True Is Set1 Superset of Set3? False

In this program, we have declared three sets, Set1, which is even numbers from 1 to 10, Set2, which contains multiple of 4 from 4 to 10 and Set3, which includes multiple of 4 from 4 to 20.

Now, we are finding if Set1 is a superset of Set2 or not. So, we can see that all the elements of Set2 are present in Set1. So, Set1 is a superset of Set2.

On the other side, we can see that not all the elements are present in Set1 of Set3, so Set1 is not a superset of Set3. That’s why the return value is False.

Finally, Python Set issuperset() Method Example is over.

**See also**

Python set intersection_update()