# Python Set isdisjoint() Method Example

Python set isdisjoint() is an inbuilt method that tells us whether two are disjoint or not. Before learning the isdisjoint() method, we should learn what is Disjoint. Two sets are known to be disjoint if they do not have any shared values. For example, if **A={1,2,3} and B={5,7,9} **are two sets, we can see that there is no common element in them, so they are known as disjoint.

See the following figure.

**Python Set isdisjoint() Method**

Content Overview

**Python Set isdisjoint()** function checks whether the two **sets** are disjoint **sets** or not. If the **sets** are disjoint, then the isdisjoint() method returns **True** else it returns **False**. The two **sets** are said to be disjoint if they do not have any common items.

**Syntax**

set1.isdisjoint(set2)

Here set1 is one set, and set2 is another set.

**Return Value**

Python isdisjoint() method returns two values, **True **if those sets are disjoint, **False **if given sets are not disjoint.

See the following code example.

# app.py # Declaring two sets # Even nums between 2 and 10 set1 = {2, 4, 6, 8, 10} # Multiple of 3 between 1 to 10 set2 = {3, 6, 9} # Prime numbers from 1 to 10 set3 = {1, 3, 5, 7} # priting both the sets print("Set1 is: ", set1) print("Set2 is : ", set2) print("Set3 is: ", set3) # Now we will find if they are disjoint print("Are Set1 and Set2 disjoint? ", set1.isdisjoint(set2)) print("Are Set1 and Set3 disjoint? ", set1.isdisjoint(set3))

**Output**

Set1 is: {2, 4, 6, 8, 10} Set2 is : {9, 3, 6} Set3 is: {1, 3, 5, 7} Are Set1 and Set2 disjoint? False Are Set1 and Set3 disjoint? True

From the output, we can see that there is a common value between Set 1 and Set2 that is 6, so they are not disjoint. That’s why the result is **False**.

Also, we can see that there are no common elements in Set1 and Set3, so they are disjoint, and the result is **True**.

**Python Set isdisjoint() method with other iterables**

When we pass the other iterables such as List, tuple, and dictionary in the isdisjoint() function, it converts them into the Set and then checks whether the sets are disjoint or not.

When converting the **dictionary to Set**, the keys are considered as the items of the converted set.

See the following code example.

# app.py # Set A A = {11, 21} # List lis lis = [11, 21, 46] # Tuple t t = (10, "Ankit") # Dictionary dict, Set is formed on Keys dict = {11: 'Eleven', 19: 'KK'} # Dictionary dict2 dict2 = {'Four': 4, 'Five': 5} print("Set A and List lis disjoint?", A.isdisjoint(lis)) print("Set A and tuple t are disjoint?", A.isdisjoint(t)) print("Set A and dict are disjoint?", A.isdisjoint(dict)) print("Set A and dict2 are disjoint?", A.isdisjoint(dict2))

**Output**

python3 app.py Set A and List lis disjoint? False Set A and tuple t are disjoint? True Set A and dict are disjoint? False Set A and dict2 are disjoint? True

So, two sets are said to be **disjoint when their intersection is null**. In simple words, they **do not have any common element** between them.

Finally, Python Set isdisjoint() Method Example is over.

**See also**

Python set intersection_update()